3.2.7 \(\int \frac {x^{3/2}}{(b x+c x^2)^{3/2}} \, dx\)

Optimal. Leaf size=23 \[ -\frac {2 \sqrt {x}}{c \sqrt {b x+c x^2}} \]

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Rubi [A]  time = 0.01, antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {648} \begin {gather*} -\frac {2 \sqrt {x}}{c \sqrt {b x+c x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^(3/2)/(b*x + c*x^2)^(3/2),x]

[Out]

(-2*Sqrt[x])/(c*Sqrt[b*x + c*x^2])

Rule 648

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^(m - 1)
*(a + b*x + c*x^2)^(p + 1))/(c*(p + 1)), x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && EqQ[c
*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] && EqQ[m + p, 0]

Rubi steps

\begin {align*} \int \frac {x^{3/2}}{\left (b x+c x^2\right )^{3/2}} \, dx &=-\frac {2 \sqrt {x}}{c \sqrt {b x+c x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 21, normalized size = 0.91 \begin {gather*} -\frac {2 \sqrt {x}}{c \sqrt {x (b+c x)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^(3/2)/(b*x + c*x^2)^(3/2),x]

[Out]

(-2*Sqrt[x])/(c*Sqrt[x*(b + c*x)])

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IntegrateAlgebraic [A]  time = 0.39, size = 30, normalized size = 1.30 \begin {gather*} -\frac {2 \sqrt {b x+c x^2}}{c \sqrt {x} (b+c x)} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^(3/2)/(b*x + c*x^2)^(3/2),x]

[Out]

(-2*Sqrt[b*x + c*x^2])/(c*Sqrt[x]*(b + c*x))

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fricas [A]  time = 0.40, size = 30, normalized size = 1.30 \begin {gather*} -\frac {2 \, \sqrt {c x^{2} + b x} \sqrt {x}}{c^{2} x^{2} + b c x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)/(c*x^2+b*x)^(3/2),x, algorithm="fricas")

[Out]

-2*sqrt(c*x^2 + b*x)*sqrt(x)/(c^2*x^2 + b*c*x)

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giac [A]  time = 0.18, size = 21, normalized size = 0.91 \begin {gather*} -\frac {2}{\sqrt {c x + b} c} + \frac {2}{\sqrt {b} c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)/(c*x^2+b*x)^(3/2),x, algorithm="giac")

[Out]

-2/(sqrt(c*x + b)*c) + 2/(sqrt(b)*c)

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maple [A]  time = 0.04, size = 25, normalized size = 1.09 \begin {gather*} -\frac {2 \left (c x +b \right ) x^{\frac {3}{2}}}{\left (c \,x^{2}+b x \right )^{\frac {3}{2}} c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)/(c*x^2+b*x)^(3/2),x)

[Out]

-2*(c*x+b)*x^(3/2)/c/(c*x^2+b*x)^(3/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{\frac {3}{2}}}{{\left (c x^{2} + b x\right )}^{\frac {3}{2}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)/(c*x^2+b*x)^(3/2),x, algorithm="maxima")

[Out]

integrate(x^(3/2)/(c*x^2 + b*x)^(3/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {x^{3/2}}{{\left (c\,x^2+b\,x\right )}^{3/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)/(b*x + c*x^2)^(3/2),x)

[Out]

int(x^(3/2)/(b*x + c*x^2)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{\frac {3}{2}}}{\left (x \left (b + c x\right )\right )^{\frac {3}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(3/2)/(c*x**2+b*x)**(3/2),x)

[Out]

Integral(x**(3/2)/(x*(b + c*x))**(3/2), x)

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